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Merge pull request #1114 from AlgorithmWithGod/0224LJH
[20251014] BOJ / P2 / 수 지우기 / 이종환
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```java
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import java.io.BufferedReader;
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import java.io.IOException;
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import java.io.InputStreamReader;
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public class Main {
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static int len;
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static int[] arr,numCnt,eraseCnt;
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static String ans;
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public static void main(String[] args) throws IOException {
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init();
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process();
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print();
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}
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private static void init() throws IOException{
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BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
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String input = br.readLine();
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len = input.length();
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arr = new int[len];
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numCnt = new int[10];
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for (int i = 0; i < len; i++) {
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arr[i] = input.charAt(i) - '0';
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numCnt[arr[i]]++;
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}
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String erase = br.readLine();
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eraseCnt = new int[10];
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for (int i = 0; i < erase.length(); i++) {
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eraseCnt[erase.charAt(i) - '0']++;
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}
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}
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private static void process() {
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// 남을 숫자 개수
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int[] remaining = new int[10];
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int totalRemain = 0;
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for (int i = 0; i < 10; i++) {
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remaining[i] = numCnt[i] - eraseCnt[i];
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totalRemain += remaining[i];
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}
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// suffix count 전처리
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int[][] suffixCnt = new int[len + 1][10];
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for (int i = len - 1; i >= 0; i--) {
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for (int d = 0; d < 10; d++) {
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suffixCnt[i][d] = suffixCnt[i + 1][d];
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}
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suffixCnt[i][arr[i]]++;
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}
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StringBuilder sb = new StringBuilder();
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int pos = 0;
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// 결과 길이만큼 반복
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for (int resultPos = 0; resultPos < totalRemain; resultPos++) {
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// 가장 큰 숫자부터 시도
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for (int num = 9; num >= 0; num--) {
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if (remaining[num] == 0) continue;
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// 원본에서 num을 찾기
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boolean found = false;
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for (int i = pos; i < len; i++) {
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if (arr[i] == num) {
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// 이 num을 선택했을 때, i+1부터 나머지를 만들 수 있는지 확인
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remaining[num]--;
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boolean canMake = true;
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for (int d = 0; d < 10; d++) {
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if (suffixCnt[i + 1][d] < remaining[d]) {
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canMake = false;
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break;
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}
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}
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if (canMake) {
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sb.append(num);
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pos = i + 1;
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found = true;
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break;
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} else {
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remaining[num]++;
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}
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}
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}
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if (found) break;
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}
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}
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ans = sb.toString();
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}
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private static void print() {
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System.out.println(ans);
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}
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}
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```

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