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doc/pub/week6/html/week6-bs.html

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@@ -2132,7 +2132,7 @@ <h2 id="the-hamiltonian-in-terms-of-pauli-boldsymbol-x-and-pauli-boldsymbol-z-ma
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<p>with</p>
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$$
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{II}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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$$
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<p>and</p>
@@ -2166,10 +2166,10 @@ <h2 id="explicit-expressions" class="anchor">Explicit expressions </h2>
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<p>In order to perform our measurements, will then need the following operators \( \boldsymbol{U} \)</p>
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$$
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\begin{align*}
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\boldsymbol{Z}\otimes\boldsymbol{I} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
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\boldsymbol{I}\otimes\boldsymbol{Z} & \boldsymbol{U}=\text{SWAP}\\
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\boldsymbol{Z}\otimes\boldsymbol{Z} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H}\\
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\boldsymbol{Z}\otimes\boldsymbol{I}\hspace{1cm} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
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\boldsymbol{I}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=\text{SWAP}\\
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\boldsymbol{Z}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X}\hspace{1cm} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H})\\
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\end{align*}
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$$
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doc/pub/week6/html/week6-reveal.html

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@@ -2172,7 +2172,7 @@ <h2 id="the-hamiltonian-in-terms-of-pauli-boldsymbol-x-and-pauli-boldsymbol-z-ma
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<p>with</p>
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<p>&nbsp;<br>
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$$
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{II}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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$$
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<p>&nbsp;<br>
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@@ -2213,10 +2213,10 @@ <h2 id="explicit-expressions">Explicit expressions </h2>
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<p>&nbsp;<br>
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$$
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\begin{align*}
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\boldsymbol{Z}\otimes\boldsymbol{I} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
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\boldsymbol{I}\otimes\boldsymbol{Z} & \boldsymbol{U}=\text{SWAP}\\
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\boldsymbol{Z}\otimes\boldsymbol{Z} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H}\\
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\boldsymbol{Z}\otimes\boldsymbol{I}\hspace{1cm} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
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\boldsymbol{I}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=\text{SWAP}\\
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\boldsymbol{Z}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X}\hspace{1cm} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H})\\
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\end{align*}
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$$
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<p>&nbsp;<br>

doc/pub/week6/html/week6-solarized.html

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@@ -2051,7 +2051,7 @@ <h2 id="the-hamiltonian-in-terms-of-pauli-boldsymbol-x-and-pauli-boldsymbol-z-ma
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<p>with</p>
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$$
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{II}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
2054+
\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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$$
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<p>and</p>
@@ -2085,10 +2085,10 @@ <h2 id="explicit-expressions">Explicit expressions </h2>
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<p>In order to perform our measurements, will then need the following operators \( \boldsymbol{U} \)</p>
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$$
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\begin{align*}
2088-
\boldsymbol{Z}\otimes\boldsymbol{I} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
2089-
\boldsymbol{I}\otimes\boldsymbol{Z} & \boldsymbol{U}=\text{SWAP}\\
2090-
\boldsymbol{Z}\otimes\boldsymbol{Z} & \boldsymbol{U}=CX_{10}\\
2091-
\boldsymbol{X}\otimes\boldsymbol{X} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H}\\
2088+
\boldsymbol{Z}\otimes\boldsymbol{I}\hspace{1cm} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
2089+
\boldsymbol{I}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=\text{SWAP}\\
2090+
\boldsymbol{Z}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X}\hspace{1cm} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H})\\
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\end{align*}
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$$
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doc/pub/week6/html/week6.html

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@@ -2128,7 +2128,7 @@ <h2 id="the-hamiltonian-in-terms-of-pauli-boldsymbol-x-and-pauli-boldsymbol-z-ma
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<p>with</p>
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$$
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\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{II}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
2131+
\mathcal{H}_0=\epsilon_{II}\boldsymbol{I}\otimes\boldsymbol{I}+\epsilon_{ZI}\boldsymbol{Z}\otimes\boldsymbol{I}+\epsilon_{IZ}\boldsymbol{I}\otimes\boldsymbol{Z}+\epsilon_{ZZ}\boldsymbol{Z}\otimes\boldsymbol{Z},
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$$
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<p>and</p>
@@ -2162,10 +2162,10 @@ <h2 id="explicit-expressions">Explicit expressions </h2>
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<p>In order to perform our measurements, will then need the following operators \( \boldsymbol{U} \)</p>
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$$
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\begin{align*}
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\boldsymbol{Z}\otimes\boldsymbol{I} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
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\boldsymbol{I}\otimes\boldsymbol{Z} & \boldsymbol{U}=\text{SWAP}\\
2167-
\boldsymbol{Z}\otimes\boldsymbol{Z} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H}\\
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\boldsymbol{Z}\otimes\boldsymbol{I}\hspace{1cm} & \boldsymbol{U}=\boldsymbol{I}\otimes\boldsymbol{I}\\
2166+
\boldsymbol{I}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=\text{SWAP}\\
2167+
\boldsymbol{Z}\otimes\boldsymbol{Z}\hspace{1cm} & \boldsymbol{U}=CX_{10}\\
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\boldsymbol{X}\otimes\boldsymbol{X}\hspace{1cm} & \boldsymbol{U}=CX_{10}(\boldsymbol{H}\otimes\boldsymbol{H})\\
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\end{align*}
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$$
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