feat: valid-anagram

Author: hozzijeong

valid-anagram/hozzijeong.js

@@ -0,0 +1,48 @@
+/**
+ * @param {string} s
+ * @param {string} t
+ * @return {boolean}
+ */
+
+ /**
+  * map을 통해 문자의 개수를 저장하고, 두 문자열의 문자 개수를 비교해서 다른 값이 있다면 false를 반환하도록 풀이를작성했습니다
+  *
+  */
+var isAnagram = function(s, t) {
+    if(s.length !== t.length) return false;
+
+    const length = s.length;
+
+    const stringMap = new Map();
+    const targetMap = new Map();
+
+    for(let i = 0; i < length; i ++){
+
+        const stringChar = s[i];
+        const currentStringMap = stringMap.get(stringChar);
+        
+        if(currentStringMap){
+            stringMap.set(stringChar, currentStringMap + 1)
+        }else{
+            stringMap.set(stringChar, 1)
+        }
+
+        const targetChar = t[i];
+        const currentTargetMap = targetMap.get(targetChar);
+
+        if(currentTargetMap){
+            targetMap.set(targetChar, currentTargetMap + 1)
+        }else{
+            targetMap.set(targetChar, 1)
+        }
+    }
+
+    for(const [char, count] of [...stringMap]){
+        const targetCount = targetMap.get(char);
+
+        if(!targetCount) return false;
+        if(targetCount !== count) return false;
+    }
+    
+    return true
+};