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MedianOfArrays.js
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68 lines (52 loc) · 1.28 KB
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/*
Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays.
The overall run time complexity should be O(log (m+n)).
*/
/**
* @param {number[]} nums1
* @param {number[]} nums2
* @return {number}
*/
function mergeAndSort(arr1, arr2) {
let merged = [];
let i = 0, j = 0;
while (i < arr1.length && j < arr2.length) {
if (arr1[i] < arr2[j]) {
merged.push(arr1[i]);
i++;
} else {
merged.push(arr2[j]);
j++;
}
}
while (i < arr1.length) {
merged.push(arr1[i]);
i++;
}
while (j < arr2.length) {
merged.push(arr2[j]);
j++;
}
return merged;
}
var findMedianSortedArrays = function(nums1, nums2) {
const merged = mergeAndSort(nums1,nums2)
let median = 0
let medianEven = 0
if (merged.length % 2 !== 0) {
median = Math.ceil(merged.length / 2) - 1
} else {
median = merged.length / 2 - 1
medianEven = median + 1
}
let i1 = merged[median]
let i2 = merged[medianEven]
let sum = 0
if (merged.length % 2 !== 0) {
sum = i1
} else {
sum = (i1 + i2) / 2
}
return sum
};
console.log(findMedianSortedArrays([1,2],[3,4]))