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linkedlist.py
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86 lines (73 loc) · 2.13 KB
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"""The LinkedList code from before is provided below.
Add three functions to the LinkedList.
"get_position" returns the element at a certain position.
The "insert" function will add an element to a particular
spot in the list.
"delete" will delete the first element with that
particular value.
Then, use "Test Run" and "Submit" to run the test cases
at the bottom."""
class Element(object):
def __init__(self, value):
self.value = value
self.next = None
class LinkedList(object):
def __init__(self, head=None):
self.head = head
def append(self, new_element):
current = self.head
if self.head:
while current.next:
current = current.next
current.next = new_element
else:
self.head = new_element
def get_position(self, position):
current = self.head
i=1
while current:
if position == i:
return current
current = current.next
i = i + 1
return None
"""Get an element from a particular position.
Assume the first position is "1".
Return "None" if position is not in the list."""
return None
def insert(self, new_element, position):
"""Insert a new node at the given position.
Assume the first position is "1".
Inserting at position 3 means between
the 2nd and 3rd elements."""
pass
def delete(self, value):
"""Delete the first node with a given value."""
pass
# Test cases
# Set up some Elements
e1 = Element(1)
e2 = Element(2)
e3 = Element(3)
e4 = Element(4)
# Start setting up a LinkedList
ll = LinkedList(e1)
ll.append(e2)
ll.append(e3)
# Test get_position
# Should print 3
print ll.head.next.next.value
# Should also print 3
print ll.get_position(3).value
# Test insert
ll.insert(e4,3)
# Should print 4 now
print ll.get_position(3).value
# Test delete
ll.delete(1)
# Should print 2 now
print ll.get_position(1).value
# Should print 4 now
print ll.get_position(2).value
# Should print 3 now
print ll.get_position(3).value