Given a directed, acyclic graph of N nodes. Find all possible paths from node 0 to node N-1, and return them in any order.
The graph is given as follows: the nodes are 0, 1, ..., graph.length - 1. graph[i] is a list of all nodes j for which the edge (i, j) exists.
Example: Input: [[1,2], [3], [3], []] Output: [[0,1,3],[0,2,3]] Explanation: The graph looks like this: 0--->1 | | v v 2--->3 There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.
Note:
- The number of nodes in the graph will be in the range
[2, 15]. - You can print different paths in any order, but you should keep the order of nodes inside one path.
Companies:
Bloomberg, Walmart Labs
// OJ: https://leetcode.com/problems/all-paths-from-source-to-target/
// Author: github.com/lzl124631x
// Time: O(N * 2^N)
// Space: O(N)
class Solution {
private:
vector<vector<int>> ans;
unordered_set<int> seen;
vector<int> path;
void dfs(vector<vector<int>>& graph, int from) {
path.push_back(from);
if (from == graph.size() - 1) ans.push_back(path);
else {
seen.insert(from);
for (int n : graph[from]) {
if (seen.find(n) != seen.end()) continue;
dfs(graph, n);
}
seen.erase(from);
}
path.pop_back();
}
public:
vector<vector<int>> allPathsSourceTarget(vector<vector<int>>& graph) {
dfs(graph, 0);
return ans;
}
};