From df43cbcd41b394dfccacee90234a85d667598c45 Mon Sep 17 00:00:00 2001
From: Saba Bestaev <bestaev.saba@gmail.com>
Date: Wed, 4 Jun 2025 20:46:43 +0300
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---
 README.md  | 60 ++++++++++++++++++++++++++++++++++++++++++++++++++++++
 english.md | 60 ++++++++++++++++++++++++++++++++++++++++++++++++++++++
 2 files changed, 120 insertions(+)

diff --git a/README.md b/README.md
index 46849bc..24ef286 100644
--- a/README.md
+++ b/README.md
@@ -1325,3 +1325,63 @@ WHERE email_verified_at IS NOT NULL;
 ```
 
 </details>
+
+93. Какой средний возраст клиентов, купивших Smartwatch (использовать наименование товара product.name) в 2024 году? [(сайт)](https://sql-academy.org/ru/trainer/tasks/93)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT AVG(sub.age) AS average_age
+FROM (
+		SELECT DISTINCT c.customer_key,
+			c.age
+		FROM Customer AS c
+			JOIN Purchase AS pu ON pu.customer_key = c.customer_key
+			JOIN Product AS p ON p.product_key = pu.product_key
+		WHERE YEAR(pu.date) = 2024
+			AND p.name = 'Smartwatch'
+	) AS sub;
+```
+
+</details>
+
+94. Вывести имена покупателей, каждый из которых приобрёл Laptop и Monitor (использовать наименование товара product.name) в марте 2024 года? [(сайт)](https://sql-academy.org/ru/trainer/tasks/94)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT c.name
+FROM Customer AS c
+	JOIN Purchase AS pu ON pu.customer_key = c.customer_key
+	JOIN Product AS p ON p.product_key = pu.product_key
+WHERE YEAR(pu.date) = 2024
+	AND MONTH(pu.date) = 3
+	AND p.name IN ('Laptop', 'Monitor')
+GROUP BY c.customer_key,
+	c.name
+HAVING COUNT(DISTINCT p.name) = 2;
+```
+
+</details>
+
+97. Посчитать количество работающих складов на текущую дату по каждому городу. Вывести только те города, у которых количество складов более 80. Данные на выходе - город, количество складов. [(сайт)](https://sql-academy.org/ru/trainer/tasks/97)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT city,
+	COUNT(*) AS warehouse_count
+FROM Warehouses
+WHERE (
+		date_close IS NULL
+		OR date_close > CURRENT_DATE()
+	)
+GROUP BY city
+HAVING warehouse_count > 80
+ORDER BY warehouse_count DESC;
+```
+
+</details>
\ No newline at end of file
diff --git a/english.md b/english.md
index 8b6562f..def2e70 100644
--- a/english.md
+++ b/english.md
@@ -1318,3 +1318,63 @@ WHERE email_verified_at IS NOT NULL;
 ```
 
 </details>
+
+93. What is the average age of customers who bought a Smartwatch (use product.name) in 2024? [(сайт)](https://sql-academy.org/ru/trainer/tasks/93)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT AVG(sub.age) AS average_age
+FROM (
+		SELECT DISTINCT c.customer_key,
+			c.age
+		FROM Customer AS c
+			JOIN Purchase AS pu ON pu.customer_key = c.customer_key
+			JOIN Product AS p ON p.product_key = pu.product_key
+		WHERE YEAR(pu.date) = 2024
+			AND p.name = 'Smartwatch'
+	) AS sub;
+```
+
+</details>
+
+94. Output the names of customers who each purchased a Laptop and Monitor (use product.name) in March 2024? [(сайт)](https://sql-academy.org/ru/trainer/tasks/94)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT c.name
+FROM Customer AS c
+	JOIN Purchase AS pu ON pu.customer_key = c.customer_key
+	JOIN Product AS p ON p.product_key = pu.product_key
+WHERE YEAR(pu.date) = 2024
+	AND MONTH(pu.date) = 3
+	AND p.name IN ('Laptop', 'Monitor')
+GROUP BY c.customer_key,
+	c.name
+HAVING COUNT(DISTINCT p.name) = 2;
+```
+
+</details>
+
+97. Calculate the number of working warehouses as of the current date for each city. Output only those cities that have more than 80 warehouses. Output data - city, number of warehouses. [(сайт)](https://sql-academy.org/ru/trainer/tasks/97)
+
+<details>
+  <summary>Решение</summary>
+
+```mysql
+SELECT city,
+	COUNT(*) AS warehouse_count
+FROM Warehouses
+WHERE (
+		date_close IS NULL
+		OR date_close > CURRENT_DATE()
+	)
+GROUP BY city
+HAVING warehouse_count > 80
+ORDER BY warehouse_count DESC;
+```
+
+</details>
\ No newline at end of file