Error in if (substr(file.name, 1, 5) != "http:") {: argument is of length zero Traceback:

[joeymizrahi]

im running the following code:
library(XBRL) xbrl_url2014 <- "https://www.sec.gov/Archives/edgar/data/1400000/000121152415000130/abki-20150531_cal.xml" old_o <- options(stringsAsFactors = FALSE) xbrl_data_aapl2014 <- xbrlDoAll(xbrl_url2014) options(old_o)

and keep getting the following error:

Error in if (substr(file.name, 1, 5) != "http:") {: argument is of length zero
Traceback:

1. xbrlDoAll(xbrl_url2014)
2. xbrl$processSchema(xbrl$getSchemaName())
3. which(discovered.files == file)
4. xbrl$getSchemaName()
5. fixFileName(dname.inst, .Call("xbrlGetSchemaName", doc.inst,
   . PACKAGE = "XBRL"))

[ABSYKS]

Just had a similar issue - it looks like you've used the linkbase calculations document instead of the XBRL instance needed ending in .xml as opposed to _cal.xml
Hope that helps.

[Karnner2]

edit the XBRL, by doing the following:
trace('XBRL', edit=TRUE)

change the XBRL code where it calls the http, to include https. The issue is not with finstr.

#if (!(substr(file.name, 1, 5) %in% c("http:", "https"))) {