Is there any way to call original function by symbol name?

[cutecutecat]

        var guard_down *sm.PatchGuard
	download_hook := "xxx.DownloadPiece"
	guard_down = sm.PatchByFullSymbolName(download_hook, func(ctx context.Context, pt peer.Task, request *peer.DownloadPieceRequest) (success bool) {
		// do something

                // temporary unpatch
		guard_down.Unpatch()
		defer guard_down.Restore()
                
                // use forceexport to fetch original function
		var function func(context.Context, peer.Task, *peer.DownloadPieceRequest) (success bool)
		err := forceexport.GetFunc(&function, download_hook)
		if err != nil {
			log.Panicf("connect target error: %s", err)
		}

                // call original function
		success = function(ctx, pt, request)
		return
	})

If the original function is unexported, and should be called inside the hooked method as above, is supermonkey provide some way to call it by symbol name rather than use forceexport?

[cch123]

I have read the code of forceexport, we can use most of its code, and only change the implementation of:

func FindFuncWithName(name string) (uintptr, error) {
}

---

我看了一下 forceexport 的代码，如果在 supermonkey 里实现的话，应该简单改改 forceexport 的 FindFuncWithName 这部分就行了，
有兴趣贡献一发么~

[cutecutecat]

没问题，但是可能要等一两周，最近手头其他工作比较忙。