Sparse data = error/no display.

[JamoCA]

If your data set of tasks doesn't dominate all of the columns, a cannot set property ' width' of undefined is thrown. If there's no tasks for "column 0", the script doesn't show an empty column.

In the demo, change the loop that assigns i (the column) to start at "1" or end at "7" to generate a smaller data set and the nothing will be rendered on the screen due to the width error.

[arelsirin]

Hi, I found the same problem. As a workaround, I added an if condition in the code, and it worked, preventing the crash. Still, I am not sure it is the best solution.

In jquery.skeduler.js, line 118:

for (var i = 0; i < args.args.length; i++) {
      if (tasks[i]) { // here, ask if that element is defined
        var width = 194 / (args.args[i] || 1);
        tasks[i].width = width;
        tasks[i].left = (args.indexes[i] * width) || 4;  
      }
}

[Fruchtgummi]

for (var i = 0; i < args.args.length; i++) {
      var width = 194 / (args.args[i] || 1);
        if( Object.prototype.toString.call( tasks[i] ) !== '[object Undefined]' ) {
            tasks[i].width = width;
            tasks[i].left = (args.indexes[i] * width) || 4;
        }
    }

ists okay