From 81739cff27540fa04c3eecd48c704c7861bc08b6 Mon Sep 17 00:00:00 2001
From: Asif Ahmad <67323237+apexx77@users.noreply.github.com>
Date: Thu, 21 Oct 2021 20:17:34 +0530
Subject: [PATCH] Created coin_change.cpp

---
 CPP/coin_change.cpp | 39 +++++++++++++++++++++++++++++++++++++++
 1 file changed, 39 insertions(+)
 create mode 100644 CPP/coin_change.cpp

diff --git a/CPP/coin_change.cpp b/CPP/coin_change.cpp
new file mode 100644
index 0000000..a45f784
--- /dev/null
+++ b/CPP/coin_change.cpp
@@ -0,0 +1,39 @@
+/*
+ Problem Statement : Given a value N, find the number of ways to make change for N cents,
+					 if we have infinite supply of each of S = { S1, S2, .. , SM } valued coins.
+*/
+
+#include<bits/stdc++.h>
+using namespace std;
+
+// Function to find the number
+
+long long int count( int S[], int m, int n ) {
+
+	long long int dp[m + 1][n + 1];
+	for (int i = 0; i <= n; i++) dp[0][i] = 0;
+	for (int i = 0; i <= m; i++) dp[i][0] = 1;
+	for (int i = 1; i <= m; i++) {
+		for (int j = 1; j <= n; j++) {
+			if (S[i - 1] <= j) {
+				dp[i][j] = dp[i][j - S[i - 1]] + dp[i - 1][j];
+			} else dp[i][j] = dp[i - 1][j];
+		}
+	} return dp[m][n];
+}
+
+// Main function
+
+int main() {
+
+	int n, m;
+	cout << "Enter the value of N and M: " << "\n";
+	cin >> n >> m;
+	int arr[m];
+	cout << "Enter the values of S1, S2, ....SM : " << "\n";
+	for (int i = 0; i < m; i++)
+		cin >> arr[i];
+	cout << "Total number of required ways is : " << count(arr, m, n) << endl;
+
+	return 0;
+}