problem6.py

#!/usr/bin/python
from tools.timeit import timeit

problem = """\
The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
"""

@timeit
def process():
    value = pow(sum(range(1,101)),2) - sum((x*x) for x in range(1,101))
    return value
    
etime, solution = process()

print "Problem :\n%s\n\n\nSolution :\n%s" % (problem, solution)
print "\nRunning time : %10.6f seconds" % (etime)