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\(M(x,y)= \) \{$multians->ans_rule(30)\} , and $BR
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\(N(x,y)= \) \{$multians->ans_rule(30)\}. (To receive credit both answers must be correct.)
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$PAR
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The term \(M(x,y) \, dx + N(x,y) \, dy\) becomes an exact differential if the left hand side above is divided by \( y^${n1}\). Integrating that new equation, the solution of the differential equation is
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\{ ans_rule(45) \} \(= C \).
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The term \(M(x,y) \, dx + N(x,y) \, dy\) becomes an exact differential if the left hand side above is divided by \( y^${n1}\). Integrating that new equation we obtain a solution of the differential equation:
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\{ $multians->ans_rule(45) \} \(= C \).
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END_TEXT
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# Can input a root, which defaults to [0,0], and another point
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# which defaults to [2,1]
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sub lcc {
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my ( $correct, $student, $anshash) = @_;
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my %ah = %{ $anshash };
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my $root = $ah{root};
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$root = [0,0] unless defined($root);
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my $other = $ah{other};
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$other = [2,1] unless defined($other);
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my $const = $student->eval(x=>$root->[0], y=>$root->[1]);
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$student = $student-$const;
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if($student== 0) {
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Value::Error("The function cannot be constant");
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return 0;
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}
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my $c1 = $student->eval(x=>$other->[0], y=>$other->[1])/
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