transparent inline apply: how to achieve the apply syntax sugar?

[TomasMikula]

Given a transparent inline def apply that generates a function,

import scala.quoted.*

class Foo[A]:
  transparent inline def apply =
    ${ Foo.go[A] }

object Foo:
  def go[A](using Quotes, Type[A]) =
    Type.of[A] match
      case '[Int] => '{ (n: Int)     => n+1 }
      case _      => '{ (n: Nothing) => n }

I'd like to be able to call foo(x) instead of foo.apply(x):

@main
def main =
  val foo = Foo[Int]
  foo.apply(1) // OK
  foo(1)       // Error: method apply in class Foo does not take parameters

Is it achievable (possibly using some inline given conversions)?

[bishabosha]

I am also looking for something like this for ops-mirror

[nicolasstucki]

A workaround for this is

-  transparent inline def apply =
+  transparent inline def apply(using inline di: DummyImplicit) =

[TomasMikula]

That worked, thanks!