Why copy string to [64]byte slice instead of converting it ?

[azr]

consistent/consistent.go

Lines 238 to 245 in 75142be

	func (c *Consistent) hashKey(key string) uint32 {
	if len(key) < 64 {
	var scratch [64]byte
	copy(scratch[:], key)
	return crc32.ChecksumIEEE(scratch[:len(key)])
	}
	return crc32.ChecksumIEEE([]byte(key))
	}

for performances reasons ?

( hi ! )

[alisanguo]

I have the same question, Did you get it?

[game1991]

When you use [] byte (key) to convert a string to a byte slice, Go allocates memory for the new byte slice. This conversion can lead to high memory usage and possible performance problems in the case of high frequency calls. Using a fixed-size array (such as [64] byte) directly, you can reuse the same memory area, avoiding memory allocation on every call.