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nodchip
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Mar 22, 2026
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| long long exp = n; |
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| long long exp = n; | ||
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| if (exp < 0) { |
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真の場合の処理と偽の場合の処理が対称になっているため、自分なら early return はしないと思います。
if (exp >= 0) {
return myPowHelper(x, exp);
} else {
return 1 / myPowHelper(x, -exp);
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| long long exp = n; |
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exp という変数名は、標準ライブラリの std::exp と被っているため、避けたほうが良いかもしれません。
https://cpprefjp.github.io/reference/cmath/exp.html
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コメントありがとうございます。
標準ライブラリに std::exp があるんですね。以後、気を付けます。
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コメントされている箇所以外は、特に違和感ありませんでした 👍 |
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今回の問題
https://leetcode.com/problems/powx-n/
次の問題
https://leetcode.com/problems/k-th-symbol-in-grammar/