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CheezItMan
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Mar 19, 2020
CheezItMan
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Nice work, you hit the main learning goals here. Excellent work.
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| # method to add a new node with the specific data value in the linked list | ||
| # insert the new node at the beginning of the linked list | ||
| def add_first(value) |
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| # method to find if the linked list contains a node with specified value | ||
| # returns true if found, false otherwise | ||
| def search(value) |
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max |
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| # method to return the min value in the linked list | ||
| # returns the data value and not the node | ||
| def find_min |
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| # method that returns the length of the singly linked list | ||
| def length |
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| # method to reverse the singly linked list | ||
| # note: the nodes should be moved and not just the values in the nodes | ||
| def reverse |
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| # find the nth node from the end and return its value | ||
| # assume indexing starts at 0 while counting to n | ||
| def find_nth_from_end(n) |
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This is one way to do it, but you can do it with less space complexity.
| # checks if the linked list has a cycle. A cycle exists if any node in the | ||
| # linked list links to a node already visited. | ||
| # returns true if a cycle is found, false otherwise. | ||
| def has_cycle |
| end | ||
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| # method that inserts a given value as a new last node in the linked list | ||
| def add_last(value) |
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| # method that returns the value of the last node in the linked list | ||
| # returns nil if the linked list is empty | ||
| def get_last |
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