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sort()を使うのは違う気がします。
"sorted in non-decreasing order"という性質を使っていないです。 |
oda
reviewed
Jun 13, 2024
| class Solution: | ||
| def sortedSquares(self, nums: List[int]) -> List[int]: | ||
| for i in range(len(nums)): | ||
| nums[i] = nums[i]*num[i] |
oda
reviewed
Jun 13, 2024
| @@ -0,0 +1,28 @@ | |||
| 977. Squares of a Sorted Array | |||
| https://leetcode.com/problems/squares-of-a-sorted-array/ | |||
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Follow up: Squaring each element and sorting the new array is very trivial, could you find an O(n) solution using a different approach?
とありますね。
どうしましょうか。二分探索で正負が変わるところを探して、そこから前と後ろに移動しながらマージソートみたいなものを書くのでどうでしょうか。
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https://leetcode.com/problems/squares-of-a-sorted-array/