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nodchip
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Mar 17, 2024
| s_num = [] | ||
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| for s_ in s: | ||
| if ord('a') <= ord(s_) <= ord('z'): |
| if ord('a') <= ord(s_) <= ord('z'): | ||
| s_num.append(ord(s_)) | ||
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| half_len = len(s_num)//2 |
There was a problem hiding this comment.
left = 0
right = len(s_num) - 1
として
whlie left < right:
...
left += 1
right -= 1
としたほうが分かりやすいと思います。ただし、個人の好みかもしれません。
| ```python | ||
| class Solution: | ||
| def isPalindrome(self, s: str) -> bool: | ||
| if len(s) <= 1: |
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https://leetcode.com/problems/valid-palindrome/