Main

debug-common-errors.js

@@ -27,6 +27,11 @@ Think about which debugging methods you found most useful and how you might appl
 console.log("Welcome to the bootcamp
 
 // What’s Wrong?
+//The opening double quote " for the string is there, but the closing double quote is missing.
+//Also, the comment is on the same line, so JavaScript treats everything after console.log("Welcome to the bootcamp as part of the string, causing a syntax error.
+
+//corrected code
+console.log("Welcome to the bootcamp");
 
 
 // Program B
@@ -40,6 +45,24 @@ for (let i = 0; i < numbers.length; i++) {
 }
 
 // What’s Wrong?
+//The issue is that the array numbers contains a string "eight" instead of a number.
+
+//When JavaScript tries to multiply "eight" by 2, it results in NaN (Not a Number), but it does not crash; instead, it prints NaN to the console.
+
+//So why might it "crash"?
+
+//If your runtime environment or later code expects only numbers and does not handle NaN, it could cause problems.
+
+//corrected code
+let numbers = [2, 4, 8];  // Replace "eight" with 8
+for (let i = 0; i < numbers.length; i++) {
+  if (typeof numbers[i] === "number") {
+    let doubled = numbers[i] * 2;
+    console.log(doubled);
+  } else {
+    console.log(`Skipping non-number value: ${numbers[i]}`);
+  }
+}
 
 
 
@@ -60,3 +83,20 @@ function isPrime(num) {
 console.log(isPrime(7)); // Expected true but gets false
 
 // What’s Wrong?
+//The logic is flipped inside the loop.
+//Right now the function returns true as soon as it finds a divisor—but true is meant to mean “is prime.”
+//So every composite number (like 4 or 9) is being marked as prime, and real primes (like 7) fall through to the return false at the end.
+
+//corrected code
+function isPrime(num) {
+  if (num < 2) return false;
+  for (let i = 2; i < num; i++) {
+    if (num % i === 0) {
+      return false;  // number has a divisor → not prime
+    }
+  }
+  return true;       // no divisors found → prime
+}
+
+console.log(isPrime(7)); // true
+