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5ky7
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Mar 3, 2026
| return 0; | ||
| } | ||
| if (position == 0) { | ||
| maxMoneyAt[position] = nums[0]; |
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nit: positionか0かに統一すると良いと思います.
Suggested change
| maxMoneyAt[position] = nums[0]; | |
| maxMoneyAt[0] = nums[0]; |
| } | ||
| if (position == 0) { | ||
| maxMoneyAt[position] = nums[0]; | ||
| return nums[0]; |
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これもnitpickですが,他のパターンは全てreturn maxMoneyAt[position]なので,統一したくなる気持ちになります.
Suggested change
| return nums[0]; | |
| return maxMoneyAt[0]; |
| // - **できるだけ高レベルな抽象化を使う**: 自分でロックを細かく制御するよりも、Actor モデルやチャネルベースの通信(Goのgoroutine + channel など)の方がバグりにくい | ||
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| // 二変数の方法でも書いておく | ||
| // もう少しいい命名がある気がするが、思いつかなかった。 |
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どこをcurrentとみるのか(2変数をcurrentとpreviousとみるか,previousとpreviousのpreviousとみるか)は人によると思いますが,この命名で問題なく読めました.
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[fyi]
個人的には RobLast, SkipLast がしっくりきました。
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全体的に読みやすかったです 👍 |
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解いた問題:https://leetcode.com/problems/house-robber/description/
次に解く問題:https://leetcode.com/problems/house-robber-ii/description/