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tom4649
reviewed
Mar 27, 2026
| return [] | ||
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| level = 0 | ||
| frontiers = deque([(root, level)]) |
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単数系 frontier の方が一般的だと思います（自分も複数形にしていました）
nodchip
reviewed
Mar 27, 2026
| - In: [], Out: [] | ||
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| BFSで解く. 前問とは異なり, 奇数レベルのときは逆順に格納するようにする | ||
| 以下はレベルごとに一括で処理をし, queueを差し替える方法 |
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解く問題
Binary Tree Zigzag Level Order Traversal
次に解く問題
Validate Binary Search Tree