I think I installed the XQuartz!! Submit Assignment 2!

Assignment 2-2020.Rmd

@@ -29,6 +29,7 @@ D1 <- read.csv("video-data.csv", header = TRUE)
 
 #Create a data frame that only contains the years 2018
 D2 <- filter(D1, year == 2018)
+D2
 ```
 
 ## Histograms
@@ -63,10 +64,10 @@ y <- c(2,4,2,3,2,4,3)
 
 #Create a table from x & y
 table1 <- table(x,y)
-
+table1
 #Display the table as a Barplot
 barplot(table1)
-
+table1
 #Create a data frame of the average total key points for each year and plot the two against each other as a lines
 
 D3 <- D1 %>% group_by(year) %>% summarise(mean_key = mean(key.points))
@@ -91,26 +92,40 @@ pairs(D5)
 1. Create a simulated data set containing 100 students, each with a score from 1-100 representing performance in an educational game. The scores should tend to cluster around 75. Also, each student should be given a classification that reflects one of four interest groups: sport, music, nature, literature.
 
 ```{r}
-#rnorm(100, 75, 15) creates a random sample with a mean of 75 and standard deviation of 20
+#rnorm(100, 75, 15) creates a random sample with a mean of 75 and standard deviation of 15
 #pmax sets a maximum value, pmin sets a minimum value
 #round rounds numbers to whole number values
 #sample draws a random samples from the groups vector according to a uniform distribution
+score <- rnorm(100, 75, 15)
+hist(score, breaks = 30)
+s1 <- data.frame(score)
+s1
+
+library(dplyr)
+s1 <- filter(s1, score <= 100)
+hist(s1$score)
 
+s2 <- data.frame(rep(100, 100-NROW(s1)))
+names(s2) <- "score"
 
-```
+s3 <- bind_rows(s1, s2)
 
+s3$studentid <- seq(1, 100, 1)
+s3$score <- round(s3$score)
+interest <- c("sport", "music","nature", "literature")
+s3$interest <- sample(interest, 100, replace = TRUE)
+s3
+```
 2. Using base R commands, draw a histogram of the scores. Change the breaks in your histogram until you think they best represent your data.
 
 ```{r}
-
+hist(s3$score, breaks = 10, ylim = c(0, 30))
 ```
-
-
 3. Create a new variable that groups the scores according to the breaks in your histogram.
 
 ```{r}
 #cut() divides the range of scores into intervals and codes the values in scores according to which interval they fall. We use a vector called `letters` as the labels, `letters` is a vector made up of the letters of the alphabet.
-
+s3$lables <- cut(s3$score, breaks = 10, labels = letters[1:10])
 ```
 
 4. Now using the colorbrewer package (RColorBrewer; http://colorbrewer2.org/#type=sequential&scheme=BuGn&n=3) design a pallette and assign it to the groups in your data on the histogram.
@@ -123,43 +138,46 @@ library(RColorBrewer)
 #Make RColorBrewer palette available to R and assign to your bins
 
 #Use named palette in histogram
-
+brewer.pal(10, "Set3")
+hist(s3$score, breaks = 10 , ylim = c(0, 30), col = brewer.pal(10, "Set3"), border = FALSE)
 ```
 
 
 5. Create a boxplot that visualizes the scores for each interest group and color each interest group a different color.
 
 ```{r}
 #Make a vector of the colors from RColorBrewer
-
+head(s3)
+boxplot(score ~ interest, data = s3)
+brewer.pal(4, "Pastel1")
+display.brewer.pal(4, "Pastel1")
+boxplot(score ~ interest, data = s3, col = brewer.pal(4, "Pastel1"), border = "grey")
 ```
-
-
 6. Now simulate a new variable that describes the number of logins that students made to the educational game. They should vary from 1-25.
 
 ```{r}
-
+(s3$logins <- sample(1:25, 100, replace = TRUE))
 ```
 
 7. Plot the relationships between logins and scores. Give the plot a title and color the dots according to interest group.
 
 ```{r}
-
-
+plot(s3$logins ~ score, data = s3, main = "All About Games", ylab = "logins", pch = 7, col = c("plum2", "mediumturquoise", "darkseagreen1", "lavender"))
 ```
 
 
 8. R contains several inbuilt data sets, one of these in called AirPassengers. Plot a line graph of the the airline passengers over time using this data set.
 
 ```{r}
-
+plot(AirPassengers)
 ```
 
 
-9. Using another inbuilt data set, iris, plot the relationships between all of the variables in the data set. Which of these relationships is it appropraiet to run a correlation on? 
+9. Using another inbuilt data set, iris, plot the relationships between all of the variables in the data set. Which of these relationships is it appropriate to run a correlation on? 
 
 ```{r}
-
+plot(iris)
+cor(iris$Petal.Length,iris$Petal.Width)
 ```
 
 # Part III - Analyzing Swirl
@@ -171,7 +189,15 @@ In this repository you will find data describing Swirl activity from the class s
 ### Instructions
 
 1. Insert a new code block
+```{r}
+
+```
+
 2. Create a data frame from the `swirl-data.csv` file called `DF1`
+```{r}
+DF1 <- read.csv("swirl-data.csv", header = TRUE)
+DF1
+```
 
 The variables are:
 
@@ -185,19 +211,52 @@ The variables are:
 `hash` - anonymyzed student ID  
 
 3. Create a new data frame that only includes the variables `hash`, `lesson_name` and `attempt` called `DF2`
+```{r}
+library(dplyr)
+DF2 <- dplyr::select(DF1, hash, lesson_name, attempt)
+DF2
+```
 
 4. Use the `group_by` function to create a data frame that sums all the attempts for each `hash` by each `lesson_name` called `DF3`
+```{r}
+library(dplyr)
+DF3 <- DF2 %>% group_by(hash, lesson_name) %>% summarise(sum = sum(attempt))
+DF3
+```
+
 
 5. On a scrap piece of paper draw what you think `DF3` would look like if all the lesson names were column names
+![script](WechatIMG806.jpeg)
 
 6. Convert `DF3` to this format  
+```{r}
+library(tidyr)
+script <- spread(DF3, lesson_name, sum, fill = NA, convert = FALSE)
+```
+
 
 7. Create a new data frame from `DF1` called `DF4` that only includes the variables `hash`, `lesson_name` and `correct`
+```{r}
+library(dplyr)
+DF4 <- select(DF1, hash, lesson_name, correct)
+```
 
 8. Convert the `correct` variable so that `TRUE` is coded as the **number** `1` and `FALSE` is coded as `0`  
+```{r}
+DF4$correct <- ifelse(DF4$correct == "FALSE", 0, 1)
+
+```
 
 9. Create a new data frame called `DF5` that provides a mean score for each student on each course
+```{r}
+library(dplyr)
+course_name <- DF1[,1]
+DF5 <- bind_cols(DF4, course_name)
+DF5 %>% group_by(hash, ...4) %>% summarise(mean = mean(correct))
+
+```
 
 10. **Extra credit** Convert the `datetime` variable into month-day-year format and create a new data frame (`DF6`) that shows the average correct for each day
 
+
 Finally use the knitr function to generate an html document from your work. Commit, Push and Pull Request your work back to the main branch of the repository. Make sure you include both the .Rmd file and the .html file.