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75 changes: 75 additions & 0 deletions CPP/Number of Islands.cpp
Original file line number Diff line number Diff line change
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//Given an m x n 2D binary grid grid which represents a map of '1's (land) and '0's (water), return the number of islands.


class Solution {
struct node{
int x;
int y;
node(int _x,int _y)
{
x=_x;
y=_y;
}
};
public:
int visited[1000][1000];
void bfs(int i,int j,int n,int m,vector<vector<char>>& grid)
{
queue<node>q;
q.push(node(i,j));
visited[i][j]=1;
cout<<i<<" "<<j<<endl;
while(!q.empty())
{
int a=q.front().x;
int b=q.front().y;
q.pop();
cout<<a<<" "<<b<<endl;
int ar1[4]={1,0,-1,0};
int ar2[4]={0,-1,0,1};
for(int k=0;k<4;k++)
{
int c=a+ar1[k];
int d=b+ar2[k];

if(c>=0 && c<n && d>=0 && d<m && visited[c][d]==0)
{
visited[c][d]=1;
q.push(node(c,d));
}
}
}
}
int numIslands(vector<vector<char>>& grid) {
int n=grid.size();
int m=grid[0].size();

for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if(grid[i][j]=='1')
{
visited[i][j]=0;
}
else{
visited[i][j]=1;
}
}
}

int count=0;
for(int i=0;i<n;i++)
{
for(int j=0;j<m;j++)
{
if(grid[i][j]=='1' && visited[i][j]==0)
{
bfs(i,j,n,m,grid);
count++;
}
}
}

return count;
}};