Create 122. Best Time to Buy and Sell Stock II.md#38
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Fuminiton
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Jun 29, 2025
| for i in range(len(prices) - 1): | ||
| if prices[i] < prices[i + 1]: | ||
| max_profit += prices[i + 1] - prices[i] | ||
| return max_profit |
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特に問題ないと思います。
個人的には i を day に変えると、より直感的になるかと思っています。
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day は自分の選択肢にはなかったので今後は選択肢に入れるようにします。ありがとうございます。
Mike0121
reviewed
Jun 29, 2025
| max_profit = 0 | ||
| index = 0 | ||
| while index < len(prices): | ||
| valley_index = find_next_lowest(index) |
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peakの対義語として、bottomでも良いかもしれません。
また、関数名で使われているので、そのままlowest, highestでも良いかと思いました。
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ありがとうございます。確かに関数名と合わせた方がわかりやすいですね。
Mike0121
reviewed
Jun 29, 2025
| ### プルリクやドキュメントを参照 | ||
| - https://github.com/hayashi-ay/leetcode/pull/56/files | ||
| - https://github.com/olsen-blue/Arai60/pull/38/files | ||
| - 株を持っている/いない場合の保有現金最大値を管理する方法 |
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DPでも(個人的に少し直感的ではないですが)解けるので、解いてみても良いかと思いました。
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DP で書いてみました。私もあまり直観的ではないなと感じています。
class Solution:
def maxProfit(self, prices: List[int]) -> int:
cash_with_stock = -prices[0]
cash_without_stock = 0
for i in range(1, len(prices)):
prev_cash_with_stock = cash_with_stock
cash_with_stock = max(cash_with_stock, cash_without_stock - prices[i])
cash_without_stock = max(cash_without_stock, prev_cash_with_stock + prices[i])
return cash_without_stock
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122. Best Time to Buy and Sell Stock II
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言語: Python